1096C - Polygon for the Angle - CodeForces Solution

brute force geometry *1600

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Python Code: 


from math import gcd


for _ in range(int(input())):
    theta = int(input())
    g = gcd(theta, 180)
    n_min = 180//g
    assert (n_min * theta)%180 == 0
    k = (n_min * theta)//180
    print(n_min + (n_min)*(k == n_min - 1))

C++ Code: 

/*
Problem: 1096C
Date: 06-01-2024 03:39 AM
*/


#include <iostream>
#include <algorithm>

#define M 998244353

using namespace std;

int T;
int n;

int main() {

	cin >> T;
	for(int k = 0; k < T; k++) {
		cin >> n;
		for(long long i = 3; i <= 360; i++) {
			if((i * (i - 2) * n) % (180 * i - 360) == 0 && n * i * (i - 2) / (180 * i - 360) <= i - 2) {
				cout << i << endl;
				break;
			}
		}
	}
}


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